Y=-16x^2+95x+7

Solution for Y=-16x^2+95x+7 equation:

=-16Y^2+95Y+7

We move all terms to the left:

-(-16Y^2+95Y+7)=0

We get rid of parentheses

16Y^2-95Y-7=0

a = 16; b = -95; c = -7;
Δ = b2-4ac
Δ = -952-4·16·(-7)
Δ = 9473
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-95)-\sqrt{9473}}{2*16}=\frac{95-\sqrt{9473}}{32}
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-95)+\sqrt{9473}}{2*16}=\frac{95+\sqrt{9473}}{32}
$